BCA manipal jaipur university 3rd sem solved assignments

PROGRAM BCA

SEMESTER III

COURSE CODE & NAME DCA2103, Computer Organization

SET-I

1. Explain von Neumann Architecture in detail.

Ans:

Structure of the IAS Computer

IAS is the first digital computer in which the von Neumann Architecture was employed. The general structure of the IAS computer is as shown in figure

 A main memory, which stores both instructions and data

 An arithmetic and logic unit (ALU) capable of operating on binary data

 A control unit,

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2. Explain in detail the different instruction formats with examples.

Ans: Instruction Formats

Instruction Format is defined as the layout of bits in an instruction in terms of its constituent parts. An Instruction Format must include opcode implicitly or explicitly and one or more operand(s). For, most instruction sets have usually mor

3. Discuss the organization of main memory.

Ans: A memory unit is the collection of storage units or devices together. The memory unit stores the binary information in the form of bits. Generally, memory/storage is classified into 2 categories:

  • Volatile Memory: This loses its data, when power is switched off.
  • Non-Volatile Memory:

SET-II

4. List and explain the mapping functions.

Ans: Mapping functions

The correspondence between the main memory and CPU are specified by a mapping function. There are three standard mapping functions namely

1. Direct mapping

2. Associative

5. What is an interrupt? Discuss the hardware actions in interrupt handling.

Ans: An interrupt is a signal emitted by a device attached to a computer or from a program within the computer. It requires the operating system (OS) to stop and figure out what to do next. An interrupt temporarily stops or terminates a service or a current process.

With Interrupt driven I/O,

6. Explain the characteristics of RISC and CISC architectures.

Ans: RISC Characteristics

Let’s take a closer look at some of the characteristics of RISC one at a time.

1. Small and Limited Numbers of Instructions

As explained earlier, to increase the speed and performance of RISC, a limited number of frequently used instructions are executed. This reduces the number of cycles per instruction but at a cost of total number of instructions executed in the same time frame.

2. Hardwired

PROGRAM BACHELOR OF COMPUTER APPLICATIONS (BCA)

SEMESTER III

COURSE CODE & NAME DCA2102 – DATA BASE MANAGEMENT SYSTEM

Set – I

1. Explain various storage devices and their characteristics.

Ans: The fastest storage media – for example, cache and main memory – are referred to as primary storage. The media in the next level in the hierarchy – for example, magnetic disks – are referred to as secondary storage, or online storage. The media in the lowest level in the hierarchy – for example, magnetic tape and optical-disk jukeboxes – are referred to as tertiary storage, or

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2. Explain the important properties of transactions that a DBMS must ensure to maintain data in the face of concurrent access and system failures

Ans: There are four important properties of transactions that a DBMS must ensure to maintain data in the face of concurrent access and system failures:

1. Users should be able to regard the execution of each transaction as atomic: either all actions are carried out or

3. What do you mean by cardinality ratio? What are its types? Explain by giving a suitable example.

Ans: In a database, the mapping cardinality or cardinality ratio means to denote the number of entities to which another entity can be linked through a certain relation set.

For a binary relationship set R between entity sets A and B, the mapping cardinality must be one of the following:

 One-to-one (1:1): An

Set – II

4. What do you mean by Normalization? How BCNF is different from 3NF?

Ans: Normalization is to reduce redundancy which means that information is to be stored only once. Storing information several times leads to wastage of storage space, and increase in the total size of the data stored. Relations are normalized so that when relations in a database are to be altered during the lifetime of the database, we do not lose information or introduce

5. Explain Join strategies for parallel processing.

Ans: We can use multiple processors for parallel computation to make the processing faster. There are many cases where multiple processors may be available for parallel computation of the join. The architecture may be different, including database machines. We will consider an architecture where all processors have access to all disks, and all processors share main memory.

1 Parallel

6. What are the features of Object -Oriented System? How it is different from RDBMS?

Ans: Object-oriented systems make these promises:

Reduced maintenance:

The primary goal of object-oriented development is the assurance that the system will enjoy a longer life while having far smaller maintenance costs. Because most of the processes within the system are encapsulated, the behaviours may be reused and incorporated into new behaviours.

Real-world modelling:

Object-oriented systems tend to model the real world in a more complete fashion than do traditional

PROGRAM BCA

SEMESTER III

COURSE CODE & NAME DCA2101 -COPUTER ORIENTED NUMERICAL METHOD

1. Find Taylor’s series of the function f(x)= 3x^5- 2x^4+ 15x^3 + 13x^2 -12x – 5 at point c  = 2.

Answer:

we know that
Taylor series of
So

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2. Evaluate √12 to four decimal place by Newton’s – Raphson formula.

Solution: Newton’s method says that f(x) ≈l(x)=f(x0)+f'(x0)(x−x0)

√12 can be found by the function f(x) =x2−12

We know that 3<√12<4, so x0=3

f'(x)=2x

3. Solve the system of equation by matrix inversion method

x+ y+ z = 1

x+ 2y+ 3z = 6

x+ 3y+ 4z = 6

Solution:

x +  y +  z = 1

x + 2y + 3z = 6

x + 3y + 4z = 6

By matrix inversion.

I will assume you already know how to find the inverse of a matrix, and how to multiply two matrices. If you don’t,  post again asking how.

SET- II

4. From the following table, estimate the number of those students who obtained marks between 40 and 45

Marks30 – 4040 – 5050 – 6060 – 7070 – 80
No. of students3142513531

Solution: Given

Marks30 – 4040 – 5050 – 6060 – 7070 – 80
No. of students3142513531

To find

The number of students who obtained marks between 40 and 45.

Solution

The Newton’s Forward Difference Formula is given as,

⇒f(a+hu)=f(a)+uΔ(fa)+https://tex.z-dn.net/?f=%5Cfrac%7Bu(u-1)%7D%7B2%7DΔ²f(a)+…+https://tex.z-dn.net/?f=%5Cfrac%7Bu(u-1)...(u-n%2B1)%7D%7Bn%7DΔⁿ(fa)

Now, we generate a forward difference table to find the maximum value i.e f(45),

x:         40  50    60      70     80

5. The population of a certain town is shown in the following table

Year x19311941195119611971
Population y40.6260.8079.95103.56132.65

Solution: Step-by-step explanation:

Given= The Population in thousand in ta tabular form

To Find= The rate of growth in percentage.

Explanation=

We have been given that the population of the certain town is given below. Find the rate of growth of the population in 1931,1941,1961, and 1971. Year x : 1931 1941 1951 1961 1971

6. Using fourth order Runga – Kutta method to find y at x= 0.1, given that dy/dx = 3e^x + 2y, y(0) = 0 and h = 0.1

Answer:

Given

Runga kutta method of fourth order, for given  We have

PROGRAM BACHELOR OF COMPUTER APPLICATIONS (BCA)

SEMESTER III

COURSE CODE & NAME DCA2104 – BASIC OF DATA COMMUNICATIONS

Set – I

1. Describe various trends in data communications and network technology. Explain Communication model in brief.

Ans: Data Communications and Networking for today’s Enterprise It is important for any enterprise to have effective and efficient data communication and networking. In this section, you will be introduced to the trends that are increasing the challenge for the business manager in planning and managing.

Trends

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2. List some difference base band and broadband transmission with some examples?

Ans:

FactorBasebandBroadband
The signal used for  Transmission.The baseband transmits the digital signal using the physical medium like wires.The broadband transmits the analog signals using optical fibers and twisted cables as a medium of transmission.

3. Differentiate between guided and unguided transmission and with some examples?

Ans: Guided transmission

In guided transmission media, you can see a cabling system that guides the data signals along a specific path. Guided media provides a guided path for propagation of signals. Twisted pairs, coaxial cables, optical fibers etc.are some of the examples for guided media.

Unguided transmission

Unguided transmission media consists of a means for the data signals to travel but nothing to guide them along a specific path. Unguided media employs an antenna for transmitting through air, vacuum or

Set – II

4. Explain different error detecting codes? Explain different Bluetooth layers.

Ans: The most popular error correcting methods are:

1. Automatic Repeat Request (ARQ)

2. Forward Error Correction (FEC)

3. Hamming Code

We will look only at the Automatic Repeat Request (ARQ) and Hamming code methods.

Automatic Repeat Request (ARQ)

A.R.Q. stands for

5. Write short on synchronous and asynchronous transmission.

Ans: The term synchronous is used to describe a continuous and consistent timed transfer of data blocks.

These types of connections are used when large amounts of data must be transferred very quickly from one location to the other. The speed of the synchronous connection is attained by transferring data in large

6. Differentiate between frequency hopping spread spectrum and direct sequence spread spectrum

Ans:

S.noFHSS (Frequency hopping spread spectrum)DSSS (Direct sequence spread spectrum
1.FH systems use a radio carrier that “hops” from frequency to frequency in a pattern known to both transmitter and receiverDS systems use a carrier that remains fixed to a specific frequency band.